Suppose this is embedded in an otherwise correct and complete program. Which version of f() will be called?

Suppose class D is derived from class B, and class B has a public
member function whose declaration is void f();. Suppose class D has its
version of the function, void f(). Here is a pointer definition and an access to a
member function..
```
B* bPtr = new D;
BPtr->f();
```

a) D::f()
b) B::f()
c) This is illegal. You can’t assign a D object to a variable of type pointer to B.

b) B::f()