You have an interface on a router with the IP address 192.168.192.113/29. What is the broadcast address the hosts will use on this LAN?
A) 192.198.192.111
B) 192.168.192.119
C) 192.168.192.127
D) 192.168.192.135
B
Explanation: B) The correct answer is 192.168.192.119 because the resident subnet ID in this case is 192.168.192.112. You can find the subnet broadcast address based on the subnet ID and mask using several methods. If you follow the decimal process in the book, the /29 converts to the mask 255.255.255.248, making the interesting octet be octet 4 with magic number 256 - 248 = 8. For the three octets where the mask = 255, copy the subnet ID (192.168.192). For the interesting octet, take the subnet ID value (112), add magic (8), and subtract 1, for.119. That makes the subnet broadcast address 192.168.192.119.
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