A patient has a whole-body O2 consumption of 320 ml/min and a measured CaO2 – CO2 of 8 ml/dl. What is the cardiac output?

a. 3.2 L/min
b. 4.0 L/min
c. 5.0 L/min
d. 7.0 L/min

ANS: B
Fick equation:
t = O2 | C(a–v)O2 ⋅ 10
In this equation, t is cardiac output (L/min), O2 is the whole-body O2 consumption (ml/min), and C(a–)O2 is the arteriovenous O2 contents difference (ml/dl). The factor of 10 converts ml/dl to ml/L. Given a normal O2 of 250 ml/min and a normal C(a–)O2 of 5 ml/dl, a normal cardiac output is calculated as follows:
t = 200 ml/min | 5 ml/dl ⋅ 10
t = 250 ml/min | 5 ml/L
t = 5.0 L/min

Health Professions

You might also like to view...

To divide a number by 10, move the decimal point:

A) One place to the left. B) Two places to the left. C) One place to the right. D) Two places to the right.

Health Professions

Which type of scaler is used interproximally?

a. Chisel b. File c. Sickle d. Hoe

Health Professions