If bulk candy costs $10.00 a kilogram and 1 pound fills a box 5 inches by 3 inches by 2 inches, what is the weight of a box 3 inches by 4 inches by 5 inches that is full of candy?

Additional information:
The volume of a rectangular box is the product of its three dimensions.
Preliminary calculations
vl (in3) = 5 (in.) * 3 (in.) * 2 (in.) = 30 (in3) v2 (in3)= 3 (in.) * 4 (in.) * 5 (in.) = 60 (in3)

Reciprocal factors
10 ($ / kg) 2.2 (kg / lb) 1 (lb / boxi)
30 (in3 / boxi) 60 (in3 / box2) 1 / 10 (kg / $)
1 / 2.2 (lb / kg) 1 (boxi / lb)
1 / 30 (boxi / in3)
1 / 60 (box2 / in3) From volume v1 above
From volume v2 above

Let x equal what you are trying to find x = ($ / box2)
Combined solution
x (lb / box2) = 1 (lb / boxi) 1 / 30 (belEi / in3) * 60 (if? / box2)
Multiply factors
x (lb / box2) = 2 (lb / box2)
Weight of candy in box2 is 2 pounds.
Simple reasoning
Boxi weighs 1 pound
Box2 is twice as large as box1
Box2 weighs 2 pounds
Since the problem did not specify which units of weight to use, you need not use kilograms.
Though not requested, the weight in kilograms is:
x (kg / box2) = 1 / 2.2 (kg / lb) * 2 (lb / box2) = 0.91 (kg / box2)
Weight in kilograms of box2 is 0.91 (kg).
Notice: Cost of candy is not need to solve problem.