When using EUI-64, what is the correct result of inverting the seventh bit of the interface ID with an interface ID of 0148:45FF:798A?

A) 0148:45DF:798A
B) 0348:45FF:798A
C) 0f48:45FF:798A
D) 0048:45FF:798A

B
Explanation: B) Only the seventh bit is affected, so the hex digit 1 (0001 in binary) becomes 3 (0011 in binary), making the full interface ID 0348:45FF:798A because the rest is unaffected.