A normal 150-lb man is breathing at a rate of 17 with a tidal volume of 450 ml. By estimation, what is his approximate alveolar ventilation?
a. 7.65 L/min
b. 5.10 L/min
c. 3.85 L/min
d. 2.60 L/min
ANS: B
VDanat averages approximately 1 ml/lb of ideal body weight (2.2 ml/kg). For a subject who weighs 150 lb (68 kg), VDanat is approximately 150 ml. For our patient the VT is 450, the RR is 17, and we will say his actual weight is his ideal body weight so 150-lb = 150 ml VD.
VA = f(VT – VD)
VA = 17(450 ml – 150 ml)
VA = 17(300 ml) = 5100 ml or 5.1 L
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