What is the output of the following, if it were embedded in an otherwise correct and complete program and run?

```
int x = 10;
while (x > 0)cout << x << “ ”;
x = x + 3;
}
cout << endl;
```
a) 10 13 16 19 . . .
b) The compiler detects that this will be an infinite loop, so it does not compile.
Insert lowercase be
c) This is an infinite loop. When compiled and run, it runs until machine limitations
stop it, or you get tired of it and kill the process.
d) 0 3 6 9.

a) 10 13 16 19 . . .
c) This is an infinite loop. When compiled and run, it runs until machine limitations