Given the following code, what will happen if the value of denom is 0?

```
double divide(int numer, int denom)
{
if (denom == 0)
throw "ERROR: Cannot divide by zero.\n";
else
return static_cast(numer)/denom;
}
```

a. Nothing will happen because there is no catch block.
b. The program will display ERROR: Cannot divide by zero.and then move to the statement following the if/else block.
c. The program will display ERROR: Cannot divide by zero.and then halt.
d. There is no throw point because there is no try block.
e. None of these

c. The program will display ERROR: Cannot divide by zero.and then halt.