Overloading and recursion look similar. Both situations call functions with the same name. Explain the difference.

What will be an ideal response?

In C++ overloading is based on the signature of the function: the function name and
the sequence of types of the arguments. If the name is the same, but the signature is
different, differing implementations are permitted.
In recursion, it is this function that is being called, with the exact same signature, not
some other function having the same name, but a different signature as in function
name overloading.