An assembly line is assigned as follows. Station 1- task A, B, and C. Station 2- task D. Station 3- task E and F. The task times are 7, 3, 2, 9, 4, and 5 minutes respective to A, B, C, D, E, and F
(Assume that there is no precedence relationship between the tasks, i.e., they can be performed in any order)
(a) Calculate the efficiency.
(b) What would the assignment of tasks to stations be using the shortest processing time heuristic (assuming the current maximum station time remains the cycle time)?
(a) Efficiency = Sum of task time / (# Stations ? Longest Station duration)
= (7 + 3 + 2 + 9 + 4 + 5)/(3 ? 12)= 83.3%
(b) Station 1 would be assigned task C for a total of 2 minutes, task B for a total of 5 minutes, Task E for a total of 9 minutes. Task F cannot be assigned because the total would be 14 minutes which is greater than the 12 maximum. Therefore Station 2 would be assigned task F for a total of 5 minutes and task A for a total of 12 minutes. Finally station 3 would be assigned task D for a total of 9 minutes.
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