Consider the following code fragment.

```
char str[10];
scanf("%s", str);
```
What will happen if scanf encounters the string "vivaciously" when scanning a value for str?

a. Since there is not enough room in str for the whole string, only "vivacious" will be stored in str.
b. Function scanf will store the entire string "vivaciously", even though there is insufficient space in str. The string will overflow str.
c. The program will abort with an error message.
d. Only "vivacious" will be scanned and stored, leaving "ly" on the input line.
e. None of the above.

B