What is the incorrect action and why does it occur?

Specification: Check to see if the user’s input is 1, 2, or 3. Write out the numeric word (such as ONE) if it is within range; otherwise, write OUT OF RANGE.
```
#include
using namespace std;
int main()
{
int user_input;
cout << “\nEnter an integer.”;
cin >> user_input;
switch(user_input)
{
case 1:
cout << “\nONE”;
case 2:
cout << “\nTWO”;
case 3:
cout << “\nTHREE”;
default: cout << “OUT OF RANGE”;
}
return 0;
}
```

The problem is that if the user enters a 1, the program will write:
ONE
TWO
THREE
OUT OF RANGE

Or, if the user enters a 2, the program writes:
TWO
THREE
OUT OF RANGE

Or, if the user enters a 3, the program writes:
THREE
OUT OF RANGE

The case blocks do not contain break statements and thus, the program executes the lines of code from where it enters the first valid case statement until the end of the switch—or if it were to finally reach a break statement.

The fix is to add break statements in the three case blocks of code.